6x^2-160x+800=0

Solution for 6x^2-160x+800=0 equation:

6x^2-160x+800=0

a = 6; b = -160; c = +800;
Δ = b2-4ac
Δ = -1602-4·6·800
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-80}{2*6}=\frac{80}{12}
=6+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+80}{2*6}=\frac{240}{12}
=20
$